9*x^2+4*x-3=0

Solution for 9*x^2+4*x-3=0 equation:

9x^2+4x-3=0

a = 9; b = 4; c = -3;
Δ = b2-4ac
Δ = 42-4·9·(-3)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{31}}{2*9}=\frac{-4-2\sqrt{31}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{31}}{2*9}=\frac{-4+2\sqrt{31}}{18}
$